-4=-4x^2-8x+5

Solution for -4=-4x^2-8x+5 equation:

-4=-4x^2-8x+5

We move all terms to the left:

-4-(-4x^2-8x+5)=0

We get rid of parentheses

4x^2+8x-5-4=0

We add all the numbers together, and all the variables

4x^2+8x-9=0

a = 4; b = 8; c = -9;
Δ = b2-4ac
Δ = 82-4·4·(-9)
Δ = 208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{208}=\sqrt{16*13}=\sqrt{16}*\sqrt{13}=4\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{13}}{2*4}=\frac{-8-4\sqrt{13}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{13}}{2*4}=\frac{-8+4\sqrt{13}}{8}
$